From 65580ff23ede9864ca713f3e7e84eb9b541c1690 Mon Sep 17 00:00:00 2001
From: Harsh Shandilya <msfjarvis@gmail.com>
Date: Thu, 5 Dec 2019 17:32:13 +0000
Subject: [PATCH] Update from Forestry.io Harsh Shandilya updated
 content/posts/teachingkotlin-part-3--caveats-coming-from-java.md

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diff --git a/content/posts/teachingkotlin-part-3--caveats-coming-from-java.md b/content/posts/teachingkotlin-part-3--caveats-coming-from-java.md
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--- a/content/posts/teachingkotlin-part-3--caveats-coming-from-java.md
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@@ -14,5 +14,4 @@ When you start migrating your Java code to Kotlin, you will encounter multiple s
 
 Java's `java.lang.String#split` [method](https://docs.oracle.com/javase/8/docs/api/java/lang/String.html#split-java.lang.String-) takes a `String` as it's first argument and creates a `Regex` out of it before attempting to split. Kotlin, however, has two variants of this method. One takes a `String` and uses it as a plaintext delimiter, and the other takes a `Regex` behaving like the Java method we mentioned earlier. Code that was directly converted from Java to Kotlin will fail to accommodate this difference, so be on the lookout.
 
-<blockquote class="twitter-tweet" data-lang="en"><p lang="en" dir="ltr"><a href="https://twitter.com/hashtag/ProTip?src=hash&ref_src=twsrc%5Etfw">#ProTip</a>: When converting your Java code to <a href="https://twitter.com/hashtag/Kotlin?src=hash&ref_src=twsrc%5Etfw">#Kotlin</a>, remember to double check if you were relying on java.lang.String's implicit Regex conversion, because Kotlin does not do it.<a href="https://t.co/u5DnDRJdx6">pic.twitter.com/u5DnDRJdx6</a></p>— Harsh Shandilya (@MSF_Jarvis) <a href="https://twitter.com/MSF_Jarvis/status/1202077283579826176?ref_src=twsrc%5Etfw">December 4, 2019</a></blockquote>
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